设为首页收藏本站 JeeStudy企业开发官网①

JEE Study|JAVA EE|企业级开发学习网

 找回密码
 立即加入

QQ登录

只需一步,快速开始

扫一扫,访问微社区

搜索
查看: 1406|回复: 0
打印 上一主题 下一主题

MySQL8.0大师之路:第9章:MySQL教程-9.9 MySQL常用查询

[复制链接]

219

主题

221

帖子

1418

积分

管理员

Rank: 9Rank: 9Rank: 9

积分
1418

最佳新人活跃会员热心会员推广达人宣传达人灌水之王突出贡献优秀版主荣誉管理论坛元老

跳转到指定楼层
楼主
发表于 2020-4-4 20:49:57 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
1.准备数据
CREATE TABLE shop (
article INT UNSIGNED DEFAULT '0000' NOT NULL,
dealer CHAR(20) DEFAULT '' NOT NULL,
price DECIMAL(16,2) DEFAULT '0.00' NOT NULL,
PRIMARY KEY(article, dealer));
INSERT INTO shop VALUES
(1,'A',3.45),(1,'B',3.99),(2,'A',10.99),(3,'B',1.45),
(3,'C',1.69),(3,'D',1.25),(4,'D',19.95);



2.根据article排序
mysql> SELECT * FROM shop ORDER BY article;
+---------+--------+-------+
| article | dealer | price |
+---------+--------+-------+
|       1 | A      |  3.45 |
|       1 | B      |  3.99 |
|       2 | A      | 10.99 |
|       3 | B      |  1.45 |
|       3 | C      |  1.69 |
|       3 | D      |  1.25 |
|       4 | D      | 19.95 |
+---------+--------+-------+
7 rows in set (0.00 sec)


3.查询article最大值
mysql> SELECT MAX(article) AS article FROM shop;
+---------+
| article |
+---------+
|       4 |
+---------+
1 row in set (0.00 sec)



4.查询价格最高的数据
mysql> SELECT article, dealer, price
    -> FROM shop
    -> WHERE price=(SELECT MAX(price) FROM shop);
+---------+--------+-------+
| article | dealer | price |
+---------+--------+-------+
|       4 | D      | 19.95 |
+---------+--------+-------+
1 row in set (0.01 sec)


另外两种写法:
mysql> SELECT s1.article, s1.dealer, s1.price
    -> FROM shop s1
    -> LEFT JOIN shop s2 ON s1.price < s2.price
    -> WHERE s2.article IS NULL;
+---------+--------+-------+
| article | dealer | price |
+---------+--------+-------+
|       4 | D      | 19.95 |
+---------+--------+-------+
1 row in set (0.00 sec)

mysql> SELECT article, dealer, price
    -> FROM shop
    -> ORDER BY price DESC
    -> LIMIT 1;
+---------+--------+-------+
| article | dealer | price |
+---------+--------+-------+
|       4 | D      | 19.95 |
+---------+--------+-------+
1 row in set (0.01 sec)


5.查询相同的article,不同的dealer,价格最高的数据
mysql> SELECT article, MAX(price) AS price
    -> FROM shop
    -> GROUP BY article
    -> ORDER BY article;
+---------+-------+
| article | price |
+---------+-------+
|       1 |  3.99 |
|       2 | 10.99 |
|       3 |  1.69 |
|       4 | 19.95 |
+---------+-------+
4 rows in set (0.01 sec)


或者
mysql> SELECT article, dealer, price
    -> FROM shop s1
    -> WHERE price=(SELECT MAX(s2.price)
    -> FROM shop s2
    -> WHERE s1.article = s2.article)
    -> ORDER BY article;
+---------+--------+-------+
| article | dealer | price |
+---------+--------+-------+
|       1 | B      |  3.99 |
|       2 | A      | 10.99 |
|       3 | C      |  1.69 |
|       4 | D      | 19.95 |
+---------+--------+-------+
4 rows in set (0.00 sec)



6.使用用户自定义临时变量存储值
查询价格最高和最低的商品信息
mysql> SELECT @min_price:=MIN(price),@max_price:=MAX(price) FROM shop;
+------------------------+------------------------+
| @min_price:=MIN(price) | @max_price:=MAX(price) |
+------------------------+------------------------+
|                   1.25 |                  19.95 |
+------------------------+------------------------+
1 row in set, 2 warnings (0.00 sec)

mysql> SELECT * FROM shop WHERE price=@min_price OR price=@max_price;
+---------+--------+-------+
| article | dealer | price |
+---------+--------+-------+
|       3 | D      |  1.25 |
|       4 | D      | 19.95 |
+---------+--------+-------+
2 rows in set (0.00 sec)











知识改变命运!

JAVA EE 学习     JAVA EE 资料
JEE Study:企业级开发学习网!
回复

使用道具 举报

高级模式
B Color Image Link Quote Code Smilies

本版积分规则

QQ|Archiver|手机版|小黑屋|JEE Study ( 京ICP备16036936   JeeStudy企业开发官网①

GMT+8, 2024-12-2 19:38 , Processed in 0.199238 second(s), 26 queries .

Powered by JeeStudy!

© 2008-2020 JEE Study 企业级开发学习网

快速回复 返回顶部 返回列表